Question

log(x-3)+log(x+6)=log 2+log 5

Answer 1

log(x-3)+log(x+6)=log2+log5

log((x-3)(x+6))=log(2*5)

(x-3)(x+6)=10

x^2+3x-18=10

X^2+3x-28=0

D=11

x1=4

x2=-7

Ответ:4