Question

26+5у-0.5у^2=2.5у^2+26

Answer 1

$26+5y-0.5 y^{2} =2.5 y^{2} +26 \ 26+5y-0.5 y^{2} -2.5 y^{2} -26=0 \ -3y^{2}+5y=0| *(-1) \ 3y^{2}-5y=0 \ y=0 \ y-5=0 \ y=5$