Question

19/84:(5целых13/42-2целых13/28+5/24)+1целая2/27-1/3х4/9=?(с решениями)

Answer 1

$frac{19}{84}:left(5frac{13}{42}-2frac{13}{28}+frac5{24}right)+1frac2{27}-frac13cdotfrac49=\ =frac{19}{84}:left(frac{223}{42}-frac{69}{28}+frac5{24}right)+frac{29}{27}-frac4{27}=\ =frac{19}{84}:left(frac{892-414+35}{168}right)+frac{25}{27}=\ =frac{19}{84}:frac{513}{168}+frac{25}{27}=frac{19}{84}cdotfrac{168}{513}+frac{25}{27}=frac2{27}+frac{25}{27}=frac{27}{27}=1$