Question

решите систему уравнений 2^x*3^y=12

                                                    3^x*2^y=18 

Answer 1

$left { {{2^{x}*3^{y}=12} atop {3^{x}*2^{y}=18}} right. \ left { {{2^{x}*3^{y}=2^{2}*3} atop {3^{x}*2^{y}=3^{2}*2}} right. \ left { {{2^{x-2}*3^{y-1}=1} atop {3^{x-2}*2^{y-1}=1}} right. \ left { {{2^{x-y-1}*3^{y-x+1}=1} atop {2^{x+y-3}*3^{y-x-3}=1} right. \ left { {{(2/3)^{x-y-1}=1} atop {(2/3)^{x+y-3}=1}} right. \ left { {{x-y=1} atop {x+y=3}} right. \ left { {{x=y+1} atop {2y=2}} right. \ left { {{y=1} atop {x=2}} right.$