Предмет: Химия, автор: Nesh

Через раствор, содержащий 5,6 г гидроксида калия,
пропустили избыток хлороводорода. Чему равно количество об-
разовавшейся соли?

Ответы

Автор ответа: Vinn
0

КОН + HCl = KCl + H2O

n(KOH) = m(KOH)/M(KOH) = 5,6/56 = 0,1 моль

По уравнению n(KCl) = n(KOH) = 0,1 моль

m(KCl) = n(KCl)*M(KCl) = 0,1*74,5 = 7,45 г.

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