Question

Срочно!!!!! Помогите пожалуйста решить!!!!!!

Answer 1

Решение
(sin4x - sin6x)/sin6x = 0

sin4x - sin6x = 0
 sin6x ≠ 0, 6x ≠ πk, k∈Z, x ≠ πk/6, k ∈Z

2si(4x- 6x)/2*cos(4x + 6x)/2 = 0
- sinx * cos5x = 0
1)  sinx = 0
x₁ = πn, n∈Z
2) cos5x = 0
5x = π/2 + πm, m∈Z
x₂ = π/10 + πm/5, m ∈Z

Answer 2

sin4x - sin6x = 0
sin6x ≠ 0, 6x ≠ πk, k∈Z, x ≠ πk/6, k ∈Z

2si(4x- 6x)/2*cos(4x + 6x)/2 = 0
- sinx * cos5x = 0
1) sinx = 0
x₁ = πn, n∈Z
2) cos5x = 0
5x = π/2 + πm, m∈Z
x₂ = π/10 + πm/5, m∈Z