Question

$y = 16tgx-16x+4 pi +9 [- pi /4; pi /4]$

Answer 1

$y'= frac{16}{cos^2x}-16\ y'=0\ frac{16}{cos^2x}-16=0\ frac{16}{cos^2x}=16\ cos^2x=1\ x=0\ y( frac{ pi }{4})= 16-4 pi +4 pi +9=25\ y(0)=4 pi +9\ y(- frac{ pi }{4})=-16+8 pi +9\ max = 25\ min = 4 pi +9$