Question

16 sinx cosx=4 корень из 2

Answer 1

16 sinxcosx = 4√2

2 sinxcosx = v2/2

sin2x = √2/2

$2x=(-1)^{n}frac{pi}{4}+pi n \x = (-1)^{n}frac{pi}{8}+frac{pi n}{2}$

n∈Z