Question

Необходимо найти x:
$( frac{49}{16} ) ^{x+1} = ( frac{4}{7}) ^ frac{1}{9}$

Answer 1

$( frac{49}{16} ) ^{x+1} = ( frac{4}{7}) ^ frac{1}{9}$
$( frac{7}{4} ) ^{2x+2} = ( frac{7}{4})^{- frac{1}{9}}$
$2x+2=- frac{1}{9}$
$2x=-2- frac{1}{9}=-frac{19}{9}$
$x=-frac{19}{18}=-1frac{1}{18}$