Question

X^log x(по основанию 3) = 9x

Answer 1

$x^{log_3 x}=9x;\ x>0;\ log^2_3 x=2+log_3 x;\ log^2_3 x-log_3 x-2=0;\ (log_3 x-2)(log_3 x+1)=0;\ 1. log_3 x=2;\ x_1=3^2=9;\ 2. log_3 x+1=0;\ log_3 x=-1;\ x_2=3^{-1}=frac{1}{3}$