Question

Выполните деление:(18х+45у )/9 (35m+42n)/7 (10m+55n)/5 (195a-65b)/13

Answer 1

Решение:

Способ 1

$ttdisplaystyle frac{(18x + 45y)}{9}=frac{18x}{9}+frac{45y}{9}=2x+5y\\\frac{(35m+42n)}{7}=frac{35m}{7}+frac{42n}{7}=5m+6n\\\frac{(10m+55n)}{5}=frac{10m}{5}+frac{55n}{5}= 2m+11n\\\frac{(195a- 65b)}{13}=frac{195a}{13} -frac{65b}{13}= 15a-5b$

Способ 2

$ttdisplaystyle frac{(18x + 45y)}{9}=frac{9(2x+5y)}{9} =2x+5y\\\frac{(35m+42n)}{7}=frac{7(5m+6n)}{7} =5m+6n\\\frac{(10m+55n)}{5}=frac{5(2m+11n)}{5} = 2m+11n\\\frac{(195a- 65b)}{13}=frac{13(15a-5b)}{13} =15a-5b$