Question

Разложите многочлен на множители:

(4л-1)^2-(5k+2)(4k-1)

Answer 1

$(4k-1)^2-(5k+2)(4k-1) =\=(16k^2-8k+1)-(20k^2-5k+8k-2)=\=16k^2-8k+1-20k^2-3k+2=-4k^2-11k+3=\=4(k-0,25)(k+3)=(k-1)(k+3)\\-4k^2-11k+3=4k^2+11k-3=0\D=121+4*4*3=169\k_1=0,25\k_2=-3$

Answer 2

$(4k-1)^2-(5k+2)(4k-1)=(4k-1)(4k-1-(5k+2))=(4k-1)(4k-1-5k-2)=(4k-1)(-k-3)=(k+3)(1-4k)$