Question

Решите пожалуйста,как можно подробнее 

1 + cos6x = 2 sin^2*5x

Answer 1

1+ cos6x=2sin²5x
1-2sin²5x+ cos6x=0
1-1+cos10x+ cos6x=0
cos10x+ cos6x=0
2cos8x•cos2x=0
1) cos8x=0 => 8x=π/2+πn => x=π/16+(π/8)•n
2) cos2x=0 => 2x=π/2+πn => x=π/4+(π/2)•n