Question

(2t-2)(5t+3)-(3t-1)(3t+2)=-4 очень срочно

 

Answer 1

(2t-2)(5t+3)-(3t-1)(3t+2)=-4

(10t^2-6t-10t-6)-(9t^2-6t-3t-2)=-4

t^2-19t-4=-4

t^2-19t=0

t(t-19)=0

t=0  и t=19

вроде бы так)