Question

Помогите срочно!!!!!!

Answer 1

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Answer 2

$1) frac{b^{3}}{b^{2}-8b+16} - frac{b ^{2} }{b-4} = frac{b^{3}}{(b-4)^{2}} - frac{b ^{2} }{b-4} =frac{b^{3}-b^{2}(b-4)}{(b-4)^{2}} =frac{b^{3}-b^{3}+4b^{2}}{(b-4)^{2}} = frac{4b^{2}}{(b-4)^{2}} \ 2) frac{b ^{2} }{b ^{2}-16 } - frac{b}{b-4} =frac{b ^{2} -b(b+4)}{b ^{2}-16 } =frac{b ^{2} -b^{2}-4b}{b ^{2}-16 } =-frac{4b}{b ^{2}-16 } \ 3)frac{4b^{2}}{(b-4)^{2}}:(-frac{4b}{b ^{2}-16 })=-frac{4b^{2}}{(b-4)^{2}}* frac{b ^{2}-16 }{4b} = -frac{b*(b+4)}{b-4} =frac{b*(b+4)}{4-b}=$

$frac{b^{2}+4b}{4-b}$