Question

4^n-2/(2^n-1-2^n-2)^2 упростите

Answer 1

=2^2n-4/(2^n-1-2^n-2)^2=2^2n*2^-4/(2^n*2^-1-2^n*2^-2)^2=2^2n*0,0625/(2^n*0.5-2^n*0,25)^2=2^2n*0,625/ 2^2n*0,625=1