Question

Решите уравнение x^3-2x^2-9x+18=0

Answer 1

x^2(x-2) -9(x-2) = 0

(x^2 - 9)(x-2) = 0

(x-3)(x+3)(x-2) = 0

x1 = 3

x2 = -3

x3 = 2

Answer 2

$x^{2}(x 2)-9(x 2)=0,$</var></p> <p><var><img src=[/tex](x^{2}-9)(x+2)=0," title="x^{2}(x+2)-9(x+2)=0," title="(x^{2}-9)(x+2)=0," title="x^{2}(x+2)-9(x+2)=0," alt="(x^{2}-9)(x+2)=0," title="x^{2}(x+2)-9(x+2)=0," />

$x^{2}(x+2)-9(x+2)=0,$

$<var></var>(x^{2}-9)(x 2)=0,$

$(x-3)(x 3)(x 2)=0$

$<var></var>(x^{2}-9)(x+2)=0,$

$(x-3)(x 3)(x 2)=0$

$<var></var>x=-2$

$<var></var>x=-3$

$<var></var>x=3$

$<var></var>x=-2$

$<var></var>x=-3$

$(x-3)(x+3)(x+2)=0$

$<var></var>x=-2$

$<var></var>x=-3$

[tex]x=3" />