Question

Докажите тождество
4a^2-(6a^2-2ab)+(3ab+2a^2)=5ab
^-степень числа

Answer 1

$4a^{2} -(6 a^{2} -2ab)+(3ab+2a ^{2})=4a^{2} -6 a^{2} +2ab+3ab+2 a^{2}= \ -2 a^{2} +5ab+2 a^{2} =5ab$