Question

Решите уравнение 1/x^2+2/x-3=0

Answer 1

$frac{1}{x^2} + frac{2}{x} -3=0;x neq 0 \ frac{1+2x-3x^2}{x^2} =0 \ 1+2x-3x^2=0 \3x^2-2x-1=0 \ D=(-2)^2-4*3*(-1)=4+12=16; sqrt{D} =4 \ x_{1}= frac{2-4}{6} =- frac{1}{3} ;x_{2}= frac{2+4}{6} =1$