Question

А)$3x^{2}+13x-10=0$

 

 

 

 

 

Б)$2x^{2}-3x=0$

 

В)$16x^{2}=49$

 

Answer 1

1)D=169+120=289

x1=-13+17/6=2/3

x2=-13-17/6=-5

2)D=9-0=9

x1=3+3/4=3/2

x2=3-3/4=0

 

Answer 2

a)

3x^2+13x-10=0

d=169-4*3*(-10)=289

x1=-13-17/2*3=-5

x2=-13+17/2*3=2/3

b)2x^2-3x=0

x(2x-3)=0

x1=0

x2=1.5

c)16x^2=49

x^2=49/16

x=7/4

x=1.75