Question

{x+y/4 -y+2/2=0
{3x+y=1
Система

Answer 1

$x+frac{y}{4}-y+frac{2}{2}=0 \ 3x+y=1$

$x+frac{y}{4}-y+1=0 \ y=1-3x$

$x+frac{1-3x}{4}-(1-3x)+1=0 \ y=1-3x$

$4x+frac{1-3x}{4}=0 \ y=1-3x$

$16x+1-3x=0 \ y=1-3x$

$13x=-1 \ y=1-3x$

$x=frac{-1}{13} \ y=1-3*frac{-1}{13}$

$x=frac{-1}{13} \ y=1-frac{-3}{13}$

$x=frac{-1}{13} \ y=frac{16}{13}$