Question

а,б
срочно!!!!!!!!!!!!!!!!!!!!

Answer 1

Формулы. a²*b²=(a*b)²; a²-b²=(a-b)*(a+b); (a-b)²=a²-2a*b+b². ➡. a) {[2x*(x-1)²]/[2x(x-1)]}²= (x-1)²-x²= (x-1+x)*(x-1-x)=-1*(-1+2x)=1-2x. b) [3(x+1)+2x(x-1)* (x-1)*(x+1)]/[(x-1)*(x+1)*(4x²+2x+6)]= (2x²+3x+1)/(4x²+2x+6).