Предмет: Алгебра,
автор: Aleks86809
Решить систему уравнений)
1)
3-х>1
х²-9≤9
2)
х²≥4
х-3<0
3)
6х-х²>0
3-2х>х
Ответы
Автор ответа:
0
1)
{3-x>1
{x²-9≤9
3-x>1
-x>1-3
-x>-2
x<2
x²-9≤9
x²-9-9≤0
x²-18≤0
(x-√18)(x+√18)≤0
(x-3√2)(x+3√2)≤0
x=3√2 x=-3√2
+ - +
------- -3√2 ------------ 3√2 --------------
\\\\\\\\\
-3√2 ≤ x ≤ 3√2
{x<2
{-3√2 ≤ x ≤ 3√2
\\\\\\\\\\\\\\\
-------- -3√2 --------- 2 ---------- 3√2 --------------
\\\\\\\\\\\\\\\\
-3√2 ≤ x <2
x∈[-3√2; 2)
2.
{x² ≥4
{x-3<0
x² ≥4
x²-4≥0
(x-2)(x+2)≥0
x=2 x=-2
+ - +
----------- -2 -------------- 2 -------------
\\\\\\\ \\\\\\\\\\\
x≤-2
x≥2
x-3<0
x<3
{x≤ -2
{x≥ 2
{x<3
\\\\\ \\\\\\\\\\\\\\\\\\
------- -2 ------------- 2 ----- 3 ----------------
\\\\\\\\\\\\\\\\\\\\
x∈(-∞; -2] U [2; 3)
3.
{6x-x²>0
{3-2x>x
6x-x²>0
x²-6x<0
x(x-6)<0
x=0 x=6
+ - +
--------- 0 ----------- 6 ------------
\\\\\\
0<x<6
3-2x>x
-2x-x> -3
-3x> -3
x<1
{0<x<6
{x<1
\\\\\\\\\\\\\\
------- 0 ---------- 1 ------------ 6 ------------------
\\\\\\\\\\\\\
0<x<1
x∈(0; 1)
{3-x>1
{x²-9≤9
3-x>1
-x>1-3
-x>-2
x<2
x²-9≤9
x²-9-9≤0
x²-18≤0
(x-√18)(x+√18)≤0
(x-3√2)(x+3√2)≤0
x=3√2 x=-3√2
+ - +
------- -3√2 ------------ 3√2 --------------
\\\\\\\\\
-3√2 ≤ x ≤ 3√2
{x<2
{-3√2 ≤ x ≤ 3√2
\\\\\\\\\\\\\\\
-------- -3√2 --------- 2 ---------- 3√2 --------------
\\\\\\\\\\\\\\\\
-3√2 ≤ x <2
x∈[-3√2; 2)
2.
{x² ≥4
{x-3<0
x² ≥4
x²-4≥0
(x-2)(x+2)≥0
x=2 x=-2
+ - +
----------- -2 -------------- 2 -------------
\\\\\\\ \\\\\\\\\\\
x≤-2
x≥2
x-3<0
x<3
{x≤ -2
{x≥ 2
{x<3
\\\\\ \\\\\\\\\\\\\\\\\\
------- -2 ------------- 2 ----- 3 ----------------
\\\\\\\\\\\\\\\\\\\\
x∈(-∞; -2] U [2; 3)
3.
{6x-x²>0
{3-2x>x
6x-x²>0
x²-6x<0
x(x-6)<0
x=0 x=6
+ - +
--------- 0 ----------- 6 ------------
\\\\\\
0<x<6
3-2x>x
-2x-x> -3
-3x> -3
x<1
{0<x<6
{x<1
\\\\\\\\\\\\\\
------- 0 ---------- 1 ------------ 6 ------------------
\\\\\\\\\\\\\
0<x<1
x∈(0; 1)
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