Question

$frac{4 x^{2} -4x}{x+3} :(2x-2,esli x=2,5;-1;$

Answer 1

......=$frac{4x(x-1)}{x+3}* frac{1}{2(x-1}= frac{4x}{x+3}$
если х=2,5,    то $frac{4*2,5}{2,5+3}= frac{10}{5,5} = 1frac{9}{11}$
если х=-1,   то$frac{4*(-1)}{-1+3}= frac{-4}{2}=-2$