Question

$(2sinx-1)(sqrt{-cosx}+1)=0$

Answer 1

1.

одз:

-cosx≥0

cosx≤0

x=-3π/2+2πk

x=-π/2+2πk

x=[-3π/2+2πk;-π/2+2πk] . k=z

2.

1)

2sinx-1=0

sinx=1/2

x=π/6+2πk . k=z-не подх под одз

x=5π/6+2πk . k=z 

2)

√-cosx+1=0

√-cosx=-1 корней нет

Ответ:x=5π/6+2πk . k=z