Question

решить неравенства (3x+12)(x^2-2x)<0

Answer 1

$(3x+12)(x^2-2x) textless 0\ 3x(x+4)(x-2) textless 0\ Nahodim korni\ 3x(x+4)(x-2)=0\ x_{1} =0;x_{2} =-4;x_{3} =2;\ (- infty;-4)-poluchaem textless 0\ (-4;0) - -poluchaem textgreater 0\ (0;2)- -poluchaem textless 0\ (2;+infty) -poluchaem textgreater 0\ Otvet: (- infty;-4)U(0;2)$