Question

6/(a-1)- 10/(a-1)^2 : 10/(a^2-1)-(2a+2)/a-1

Answer 1

$frac{6}{a-1}-frac{10}{(a-1)^{2}}:frac{10}{a^{2}-1}-frac{2a+2}{a-1}=frac{6}{a-1}-frac{10}{(a-1)^{2}}cdot frac{(a-1)(a+1)}{10}-frac{2a+2}{a-1}=\=frac{6}{a-1}-frac{a+1}{a-1}}-frac{2a+2}{a-1}=frac{6-a-1-2a-2}{a-1}=frac{-3a+3}{a-1}=frac{-3(a-1)}{a-1}=-3$