Question

(х-2)/5+(2х-5)/4-(1-4х)/20=4-х

Answer 1

$frac{(x-2)}{5}+ frac{(2x-5)}{4} - frac{(1-4x)}{20}=(4-x)$
$4(x-2)+5(2x-5)-(1-4x)=20(4-x)$
$4x-8+10x-25-1+4x=80-20x$
$4x+10x+4x+20x=80+8+25+1$
$38x=114$
x=3