Question

найдите:

        ____

а) ∫√5-4x dx

б) ∫     dx      

        1+16x²

Answer 1

$a)int{sqrt{5-4x}} dx=frac{2*(5-4x)^frac{3}{2}}{3*4}=frac{(5-4x)^frac{3}{2}}{6}+C\ b)int{frac{dx}{1+16x^2}}=frac{arctg4x}{4}+C$