Question

4дробьx-2+ xдробьx-4=1

Answer 1

$frac{4}{x-2}+ frac{x}{x-4} =1|*(x-2)(x-4) neq 0\\x neq 2; x neq 4\\4(x-4)+x(x-2)=(x-2)(x-4)\\4x-16+x^2-2x=x^2-6x+8\\2x+6x=16+8\\8x=24\\x=3$