Question

решите пожалуйста систему уравнений 2x^2-y=2 и x-y=1

Answer 1

$left { {{2x^2-y=2,} atop {x-y=1;}} right. left { {{2x^2-(x-1)=2,} atop {y=x-1;}} right. left { {{2x^2-x-1=0,} atop {y=x-1;}} right. \ D=9, \ x_1=-0,5; x_2=1; \ left { {{ left [ {{x=-0,5,} atop {x=1;}} right. } atop {y=x-1;}} right. left [ {{ left { {{x=-0,5,} atop {y=-1,5;}} right. } atop { left { {{x=1,} atop {y=0;}} right.}} right. \ (-0,5;-1,5), (1;0)$

Answer 2

x=1+y
2(1+y)^2-y=2
2(1+y^2)-y=2
2+2y^2-y=2
y^2=0
y=0
x=1+0
x=1
проверка:
1-0=1