Question

помогите решить систему

{x^3-y^3=37
{x-y=1

Answer 1

$left { {{(x-y)( x^{2} +xy+y^2)=37} atop {x-y=1}} right. \ left { {{x^2+xy+y^2=37} atop {x=y+1}}right. \ (y+1)^2+(y+1)y+y^2=37 \ y^2+2y+1+y^2+y+y^2=37 \ 3y^2+3y-36=0 \ y^2+y-12=0 \ y_{12}= frac{-1+-7}{2}=-4;3 \ x_{12}=-3;4$
зн. решение:(-3;-4);(4;3)

Answer 2

спасибо))