Question

(√2-3)^2(11+6√2) (√3-1)^2(4+2√3)

Answer 1

$(11-6 sqrt{2})(11+6 sqrt{2}) (4-2 sqrt{3}+1)(4+2 sqrt{3})= \ (121-36*2)*(16-4*3)=(121-72)*4=48*4=192$