Question

вычислите $frac{ sqrt{3} + sqrt{2} }{ sqrt{3} - sqrt{2} }$ с точностью до 0,1

Answer 1

$frac{sqrt{3}+sqrt{2}}{sqrt{3}-sqrt{2}}=frac{(sqrt{3}+sqrt{2})*(sqrt{3}+sqrt{2})}{(sqrt{3}-sqrt{2})(sqrt{3}+sqrt{2})}=frac{(sqrt{3}+sqrt{2})^2}{(sqrt{3})^2-(sqrt{2})^2}=frac{(sqrt{3})^2+2*sqrt{3}*sqrt{6}+(sqrt{2})^2}{2-1}=\=3+2sqrt{6}+2approx5+2*2.5approx5+5approx10$