Question

x^2 + 2y = 12
2x - y = 10

Answer 1

$left { {{x^2+2y=12} atop {2x-y=10}} right. \y=2x-10 \x^2+2(2x-10)=12 \x^2+4x-20-12=0 \x^2+4x-32=0 \D=16+128=144=12^2 \x_1= frac{-4+12}{2} =4 \x_2= frac{-16}{2} =-8 \y_1=2*4-10=8-10=-2 \y_2=-8*2-10=-16-10=-26$
Ответ: (4;-2), (-8;-26)