Question

решите неравенство log1/3 (12-x)<2

Answer 1

$log_{1/3}(12-x) textless 2\OD3:\12-x textgreater 0\x textless 12\\log_{1/3}(12-x) textless log_{1/3} frac{1}{9}\0 textless frac{1}{3} textless 1\\12-x textgreater frac{1}{9} \\x textless 12- frac{1}{9}\\x textless 11 frac{8}{9}\\xin (-infty;11 frac{8}{9})$