Question

решите (x+14)в квадрате =56x

Answer 1

$(x+14)^2=56x \ \ (a+b)^2=a^2+2ab+b^2 \ x^2+28x+196=56x \ x^2-28x+196=0 \ a=1;b=-28;c=196 \ \ Delta=(-28)^2-4*196=784-784=0 \ x_0=- frac{b}{2a}= frac{28}{2}=14$