Question

помогите lg(3x-7)<=lg(x+1)

Answer 1

$lg(3x-7) leq lg(x+1)\ left { {{3x-7 textgreater 0} atop {x+1 textgreater 0}} right.\\ left { {{3x textgreater 7} atop {x textgreater -1}} right. \\ left { {{x textgreater 2 frac{1}{3} } atop {x textgreater -1}} right.= textgreater x textgreater 2 frac{1}{3}\\3x-7 leq x+1\3x-x leq 1+7\2x leq 8\x leq 4\\xin(2 frac{1}{3};4]$