Question

2x^4 - 5x^2 + 2 = 0 через дискриминант

Answer 1

2х^4-5x^2+2=0            x^2=t
2t^2-5t+2=0
D=25-16=9=3^2
t1=(5+3)/2=2
t2=(5-3)/2=1/2

x^2=2        x^2=1/2
x=2;-2        x=-√(1/2);√(1/2)