Question

разложить на множители:
а)2х^2-8х^5
б)5х-10ху
в )25+10b+b^2

Answer 1

$1. 2x^2-8x^5=2x^2(1-4x^3)=-2x^2(4x^3-1) \ 2. 5x-10xy=5x(1-2y)=-5x(2y-1); \ 3. 25+10b+b^2=(b+5)^2=25+5b+5b+b^2= \ =(25+5b)+(b^2+5b)=5(5+b)b(b+5)=(5+b)(5+b)$