Question

а)х^3 7х^2 7х-1=0 б)√х+14=х-6

Answer 1

$sqrt{x+14}=x-6 \ x+14=(x-6)^2 \ x+14=x^2-12x+36 \ -x^2+13x-22=0 \ D=b^2-4ac=81 \ x_1_,_2= frac{-b^+_- sqrt{D} }{2a} \ x_1=11 \ x_2=2$