Question

Вычислить,даю 99 баллов.

Answer 1

$sqrt{28-10 sqrt{3} } (5+ sqrt{3} )= sqrt{25-10 sqrt{3}+3 } (5+ sqrt{3} )= \ =sqrt{5^2-2*5* sqrt{3}+( sqrt{3} )^2 } (5+ sqrt{3} )= sqrt{(5- sqrt{3} )^2} (5+ sqrt{3} )= \ =(5-sqrt{3}) (5+ sqrt{3} )=5^2-( sqrt{3} )^2=25-3=22$


$sqrt[4]{6-2 sqrt{5} } * sqrt[4]{6-2 sqrt{5}} = sqrt[4]{(6-2 sqrt{5})( 6+2 sqrt{5} ) } = sqrt[4]{6^2-(2 sqrt{5} )^2 }= \ sqrt[4]{36-4*5 }=sqrt[4]{36-20 }=sqrt[4]{16 }=sqrt[4]{2^4 }=2$

Answer 2

$3)...= sqrt{(5- sqrt{3})^2 } (5+ sqrt{3} )=(5- sqrt{3} )(5+ sqrt{3} )=25-3=22$
$4)...= sqrt[4]{(6-2 sqrt{5} )(6+2 sqrt{5} )} = sqrt[4]{36-20} = sqrt[4]{16} =2$