Question

(-pi)^2*sin(pi*0.2)

Сколько будет?

Answer 1

$(-\pi )^2\cdot sin(\pi \cdot 0,2)=\pi ^2\cdot sin\frac{\pi}{5}=\pi ^2\cdot \frac{\sqrt{5-\sqrt5}}{2\sqrt2}=\frac{\pi ^2}{2}\cdot \sqrt{\frac{5-\sqrt5}{2}}$