Question

$left { {{Log_6 x - 2y = 3} atop {2Log_6 x + y = 1}} right$

Answer 1

$begin{cases} log_{6}x-2y=3\2log_{6}x+y=1end{cases}=begin{cases} log_{6}x=2y+3\2(3+2y)+y=1end{cases}$$=begin{cases} log_{6}x=2y+3\6+4y+y=1end{cases}=begin{cases} log_{6}x=2y+3\5y=-5end{cases}=begin{cases} log_{6}x=3-2\y=-1end{cases}$$=begin{cases} log_{6}x=1\y=-1end{cases}=begin{cases} x=6\y=-1end{cases}$