Question

Решите уравнение cos4x+cos2x=0

Answer 1

cos4x+cos2x=0
2cos²2x-1+cos2x=0
cos2x=a
2a²+a-1=0
D=1+8=9
a1=(-1-3)/4=-1⇒cos2x=-1⇒2x=π+2πn⇒x=π/2+πn,n∈z
a2=(-1+3)/4=1/2⇒cos2x=1/2⇒2x=+-π/3+2πk⇒x=+-π/6+πk,k∈z