Question

Разложите на множители:
1) -3х²+12х-12
2) 16m²-(m-n)²

Answer 1

$1) -3x^2+12x-12=-3(x^2-4x-4)=-3(x-2)^2; \ 2) 16m^2-(m-n)^2=16m^2-n^2+2mn-m^2=-n^2+2mn+15m^2= \ =-n^2+5mn-3mn+15m^2= (-n^2-3mn)+(5mn+15m^2)= \ =-n(n+3m)+5m(n+3m)= (n+3m)(5m-n)$