Question

Вычислить производную в точке.
1) F(x)=3x^4 - 2x^2 + 4x-1 ; x= -1
2) F(x)= (3-x^2)*(4+x^2) ; в.т x= -2
3) F(x)= x^2+1/x^3+1 в.т x=1

Answer 1

$f(x)=3x^4-2x^2+4x-1\f`(x)=3*4x^3-2*2x+4=12x^3-4x+4\f`(-1)=12(-1)^3-4(-1)+4=-12+4+4=-4\\f(x)=(3-x^2)(4+x^2)\f`(x)=(3-x^2)`(4+x^2)+(3-x^2)(4+x^2)`=\=-2x(4+x^2)+2x(3-x^2)=-8x-2x^2+6x-2x^2=-4x^2-2x\f`(-2)=-4(-2)^2-2(-2)=-4*2+4=-8+4=-4\\f(x)= frac{x^2+1}{x^3+1}\\f`(x)= frac{(x^2+1)`(x^3+1)-(x^2+1)(x^3+1)`}{(x^3+1)^2}= frac{2x(x^3+1)-3x^2(x^2+1)}{(x^3+1)^2}=\\= frac{2x^4+2x-3x^4-3x^2}{(x^3+1)^2}= frac{-x^4-3x^2+2x}{(x^3+1)^2}$

$f`(1)= frac{-1^4-3*1^2+2*1}{(1^3+1)^2}= frac{-1-3+2}{(1+1)^2}= frac{-2}{2^2}= frac{-2}{4}=-0,5$