Предмет: Алгебра, автор: timergalieva

Периметр прямоугольника равен 36 м. Если его длину увеличить на 1 м, а ширину увеличить на 2 м, то его площадь увеличится на 30 кв.м. Определите площадь первоначального прямоугольника.

Ответы

Автор ответа: Kolobok15

пусть сторона прямоугольника х, тогда вторая (36-2х)/2 = 18-x. площадь прямоугольника
18х-x^2. согласно условия составим уравнение
(х+1)(18-x+2)-18х+x^2 = 30

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