Question

2sin(7п/2-х)*sinx=cosx помогите решить

Answer 1

2sin(2n+3π/2-x)*sinx=cosx
2sin(3π/2+x)sinx=cosx
-2cosxsinx=cosx
cosx+2cosxsinx=0
cosx(1+2sinx)=0
cosx=0⇒x=π/2+ππn,n∈Z
sinx=-1/2⇒x=(-1)^(k+1)π/6+πk,k∈Z