Question

реебят,пожалуста,помогите решить,срочно надо)

sin^2(3x-пи/8)=1/2

Answer 1

1)sin(3x-пи/8)=1/2                                           и              2)sin(3x-пи/8)= - 1/2

3х - pi/8 = (-1)^n (pi/6) +pin                                                3х - pi/8 = (-1)^(n+1) (pi/6) +pin  

3x = (-1)^n (pi/6) +pi/6+pin                                                  3x = (-1)^(n+1) (pi/6) +pi/6+pin   

x = (-1)^n (pi/18) +pi/18+pin /3                                             x = (-1)^(n+1) (pi/18) +pi/18+pin /3

 

Answer 2

$sin^2(3x-frac{pi}{8})=frac{1}{2}\ sin^2alpha = frac{1}{2}\ frac{1-cos2alpha}{2}=frac{1}{2}\ 1-cos2alpha=1\ cos2alpha=0\ 2alpha=frac{pi}{2}\ alpha = frac{pi}{4}\ 3x-frac{pi}{8} = frac{pi}{4}\ 3x = frac{3pi}{8}\ x = frac{pi}{8}$